-(-3)^-2-2^2-(-k-3)=-4^2-(3k-4)

Solution for -(-3)^-2-2^2-(-k-3)=-4^2-(3k-4) equation:

-(-3)^-2-2^2-(-k-3)=-4^2-(3k-4)

We move all terms to the left:

-(-3)^-2-2^2-(-k-3)-(-4^2-(3k-4))=0

We add all the numbers together, and all the variables

-(-1k-3)-(-4^2-(3k-4))-2-(-3)^-2^2=0

We add all the numbers together, and all the variables

-(-1k-3)-(-4^2-(3k-4))-2.0123456790123=0

We get rid of parentheses

1k-(-4^2-(3k-4))+3-2.0123456790123=0


We calculate terms in parentheses: -(-4^2-(3k-4)), so:

-4^2-(3k-4)

determiningTheFunctionDomain
-(3k-4)-4^2

We add all the numbers together, and all the variables

-(3k-4)-16

We get rid of parentheses

-3k+4-16

We add all the numbers together, and all the variables

-3k-12

Back to the equation:

-(-3k-12)


We add all the numbers together, and all the variables

k-(-3k-12)+0.9876543209877=0

We get rid of parentheses

k+3k+12+0.9876543209877=0

We add all the numbers together, and all the variables

4k+12.987654320988=0

We move all terms containing k to the left, all other terms to the right

4k=-12.987654320988

k=-12.987654320988/4

k=-3+0.987654320988/4